How do I... List the most popular pages?

There is currently no built-in function for retrieving the most popular pages.  However, there is an Deki API function which can be invoked from DekiScript!

For this sample, we use uri.build to build the URI from the site.api URi.  Then, we use web.xml to fetch the document from it (see what the XML looks like).  Now, we iterate over all <page> elements in the document and print out foreach the link, title, and view count using xml.text.

DekiScript retrieves this information as the anonymous user (it does not pass on the context of the current user), so if your MindTouch is private, than this code snippet will return no pages.

<ul block="var pages = web.xml(uri.build(site.api, ['pages', 'popular'], {}))['page']">
    <li foreach="var p in pages" where="__count &lt; 10">{{ web.link(uri.build(site.uri, "index.php", { title: xml.text(p, 'path') ?? "" }), xml.text(p, 'title')) }} ({{ num.format(xml.text(p, 'metrics/metric.views'), '#,#00') }} views)</li>
</ul>

Sample output

• MindTouch Community Portal (1,202,636 views)
• Deki - English (393,217 views)
• Extensions (182,461 views)
• MindTouch In the Wild (150,063 views)
• FAQ (148,865 views)
• Configuration (100,113 views)
• Release (92,231 views)
• User Manual (87,079 views)
• Sandbox (85,715 views)
• SoCal Fire (82,953 views)

var pages = wiki.api(site.api & 'pages/popular')['page'];
<ul>
    foreach(var p in pages where __count < 10) {
        <li>
            web.link(site.uri & "index.php" & { title: xml.text(p, 'path') ?? "" }, xml.text(p, 'title')); 
            " ("; 
            num.format(xml.text(p, 'metrics/metric.views'), '#,#00'); 
            " views)";
        </li>
    }
</ul>